Question

2 men and 3 women perform a work in 8 days, 6 women and 8 children perform the same work in 4 days and 1 man and 2 children perform the same work in 16 days. find the number of days 2 men, 3 women and 8 children shall take to perform the same work:​

Answer 1

Answer:

(2M+3W)×10=(3M+2W)×8

M/W=7/2

=(2×7+3×2)×10

=20× 10

=2×7+2=16

=>200/16=25/2

=12-1/2

Step-by-step explanation:

Answer is 12 and a half days.