2 men and 3 women perform a work in 8 days,
6 women and 8 children perform the same
work in 4 days and 1 man and 2 children
perform the same work in 16 days. Find the
number of days 2 men, 3 women and 8 children
take to perform the same work:
(a) 2
(b) 3
(c) 4
(d) 6
Answers
Answered by
1
Answer:
(2M+3W)×10=(3M+2W)×8
M/W=7/2
=(2×7+3×2)×10
=20× 10
=2×7+2=16
=>200/16=25/2
=12-1/2
Step-by-step explanation:
Answer -12and half days.
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