2 men and 4 boys can do a work in 8 days. 4 men and 2 boys can do the work in 6 days. How many days required for 1 man and 1 boys for the same work
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Answer:
8(2M+4B) = 6(4M+2B)
24M - 16M = 32B - 12B
M/B = 5/2
Total work = 8(2*5+4*2) = 144 unit
Done by 1M + 1B in = (144/7) days .(Ans.)
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