Math, asked by lekshmimadhu5547, 1 month ago

2 men and 4 women can do work in 28 days . then number of days wanted to complete the work if 4 men and 8 women jointly worked ?​

Answers

Answered by jasminekaur3865
1

4 men can finish the work in 18 days.

So, 1 man working alone will finish the work in 4×18 days or 72 days.

In 1 day, he will have finished 1/72 of the work.

4 women can finish the work in 28 days.

So, 1 woman working alone will finish the work in 4×28 days or 112 days.

In 1 day, she will have finished 1/112 of the work.

In 1 day, 9 men finish (9× 1/72) of the work or 1/8 of the work.

In 1 day, 12 women finish (12 × 1/112) of the work or 3/28 of the work.

Working together, 9 men and 12 women can finish (1/8 + 3/28) of the work in 1 day.

1/8 + 3/28 = 7/56 + 6/56 = 13/56 of the work.

Length of time taken working together = 1 ÷ 13/56 = 56/13 days.

Answer: 56/13 days

Answered by kv44489
2

Answer:

Men and women can do same amount of work :-

If 2 men and 4 women can do a work in 28 days => ( 2 + 4 ) = 6 person can do work in 28 days.

then, 4 men and 8 women can do

same work in days => ( 4 + 8 ) = 12 person can do a work in days.

According to question :-

If 6 person can do a work in = 28 days.

then, 1 person can do the same work in

= ( 6 × 28 ) days.

thus, 12 person can do the same work in => [ ( 28 × 6 ) / 12 ] days

=> 14 days

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