Math, asked by sonam9816463456, 9 months ago

2 men and 5 boys can do a piece of work in 4 days while 4 men and 4 boys can do it in 3 days, how long would it take one man alone to do it and in how many days​

Answers

Answered by masterstroke360
3

Answer:

Total time taken by one man to complete the job = 18 days.

Step-by-step explanation:

Let one man complete the work in 1/x days and one boy completes the work in 1/y days.

Now, 2 men and 5 boys can finish a piece of job in 4 days

⇒ 2x + 5y = 1/4

⇒ 8x + 20y = 1 .........(1)

Also, 4 men and 4 boys finish it in 3 days

⇒ 4x + 4y = 1/3

⇒ 12x + 12y = 1 ........(2)

Now, solving the equations (1) and (2)

We get 1/x = 18 and 1/y = 36

So, Total time taken by one man to complete the job = 18 days and Total time taken by one boy to complete the job = 36 days.

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Answered by MohnishSingh
0

Answer:

Total time taken by one man to complete the job = 18 days

If you need the formula, you can comment me in the comments section.

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