2 men and 5 boys can do a piece of work in 4 days while 4 men and 4 boys can do it in 3 days how long would it take one man or one boy to do it
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let time taken by 1 men per day= 1/x
let time taken by 1 boy per day = 1/y
according to question
2/x +5/y = 1/4
and also
4/x+ 4/y = 1/3
after solving 1st equation we get
let 1/x = p and 1/y = q
there fore 2p+5q = 1/4
8p+20q= 1 ..........(1)
2nd eq.
same with it
4p+4q =1/3
12p+12q = 1..........(2)
by substitution method
in 1st eq.
p=1-20q/8....(3)
put eq 3 in eq 2
12(1-20q/8)+4q =1
it gives
(12-240q+32q)=4
-208q = -8
q = 8/208
q= 1/16
put q = 1/16 in eq 3
p=(1-20×1/16)/8
then after solving it u will get value of p
then put value of p and q in 1/x and 1/y to get x and y
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