2 men and 5 boys together can finish a pice of work in 4 days while 3 men and 6 boys can finish it in 3 days ..
find the time taken by one man to finish the work
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let one man can do whole work in x days and a boy be y
then,1 man's work =1/x
and,1 boy's work=1/y
A/q
2/x+5/y=1/4
2a+5b=1/4 ....(1) where 1/x=a,1/y=b
also
3/x+6/y=1/3
3a+6b=1/3....(2)
multilply (1)by 3 and (2) by 2
6a+15b=3/4
6a+12b=2/3
subtract
3b=1/12
b=1/36
put b=1/36 in (1)
2a+5*1/36=1/4
2a=1/4-5/36
2a=1/9
a=1/18
b=1/x=1/36
x=36
a=1/y=1/18
y=18
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