2 men and 5 chilren can finish 1/2 portion of work in 5 days while 3 men and 4 children can finish 1/3 portion of it in 3 days. How many days will 9 men take to entire work
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Step-by-step explanation:
2 men and 5 children can finish 1/2 portion of the work in 5 days, means that
2 men and 5 children can finish the whole work in 10 days.
3 men and 4 children can finish 1/3 portion of the work in 3 days, means that
3 men and 4 children can finish the whole work in 9 days.
The work requires 20 man-days and 50 child-days or
27 man-days and 36 child-days.
Or 20 md+ 50 cd = 27 md + 36 cd, or
50 cd - 36 cd = 14 cd = 27 md - 20 md = 7 md. Or 1 man is equal to 2 children.
Thus the whole work requires 20 man-days + 50 child-days-man/2children
= 20 + 25 = 45 man-days.
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