2 men and 5 women can do a piece of work in 4 days while one man and one woman can finish it in 12 days. How long would it take for 1 man to do the work
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Let one man do the work alone in m days.
Let one boy do the work alone in b days.
In one day 1m part of the work is done by 1 man and
in one day 1b part of the work is done by 1 boy.
Now by given condition we have
2×1m+3×1b=110 ⋯(A)
(work done by 2 men and 3 boys in one day)
We also have
3×1m+2×1b=18 ⋯(B)
Solving above two equations we get
1b=1100 and 1m=7200
We are asked to find how many days will 2men and 1 boy take.
First we find out work completed in one day by 2 men and 1 boy
=2×7200+1100=8100=112.5
Thus the work will be completed in 12.5days
Let one boy do the work alone in b days.
In one day 1m part of the work is done by 1 man and
in one day 1b part of the work is done by 1 boy.
Now by given condition we have
2×1m+3×1b=110 ⋯(A)
(work done by 2 men and 3 boys in one day)
We also have
3×1m+2×1b=18 ⋯(B)
Solving above two equations we get
1b=1100 and 1m=7200
We are asked to find how many days will 2men and 1 boy take.
First we find out work completed in one day by 2 men and 1 boy
=2×7200+1100=8100=112.5
Thus the work will be completed in 12.5days
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