Question

2 men and 7 boys can do a piece of work. the same work is done in 3 days by 4 men and 4. how long would it take one man to complete the work and one boy to do it separately?​

Answer 1

Let one man’s one day work be x

Let one boy’s one day work be y

2x+7y=1/14 ... (1)

3x + 8y = 1 /11 ... (2)

Equating (1) & (2), x = 1 / 77 and y = 1/ 154

Hence, the days taken to complete by 8 men and 6 boys

= [8(177)+6(1154)]

=16+6154=22154=17=7days

3 times the work can be completed by 8 men and 6 boys = 3 x 7 = 21 days.