Question

2 men and 7 boys complete a piece of work in 8 days. 4 men and 4 boys can do the same in
6 days. Find the number of days required to complete the work by 1 man​

Answer 1

Answer:

let work through to men=x

let work through to boy =y

then

2x+7y=8....equation(1)

4x+4y=6....equation (2)

multiple equation 1 by 2

2x+7y=8....×2

then,

4x+14y=16

4x+4y=6

(-). (-).= (-)

10y=10

y=10÷10

y=1

putting the value of y in equation 1

therefore

2x+7×1=8

2x=8-7

x=1/2

1 day required to complete the work by 1 man.

... Ans