2 men and 7 women can together finish a work in 4 days , while 4 men and 4 women can finish it in 3 days . Find the time taken by one man alone to finish the work , and also that taken by one women alone .
Answers
Answer:
Step-by-step explanation:
Let 1 woman can finish the embroidery work in 'x' days
1 man can finish it in 'y' days.
A woman's one day work = 1/xand a man's one day work = 1/y
A.T.Q. 2/x + 5/y = 1/4 and3/x + 6/y = 1/3
Let 1/x = a and 1/y = b
Now, 2a + 5b = 1/4 _(1)and 3a + 6b = 1/3 _(2)Multiplying _
(1) by 3 and _(2) by 2 and subtracting6a + 15b = 1/46a + 18b = 1/3___________0 + 3b = 1/4 - 1/3=> 3b = 1/12
=> b = 1/(12×3)
=> b = 1/36Putting b = 1/36 in _(1)2a + 5(1/36) = 1/4
=> 72a + 5 = 36/4=> 72a + 5 = 9
=> 72a = 9 - 5
=> 72a = 4
=> a = 4/72
=> a = 1/18
Now, a = 1/x = 1/18
=> x = 18And, b = 1/y = 1/36
=> y = 36
So,
1 woman can finish the embroidery work in 18 days and 1 man can finish the work in 36 days.
Answer:
One men can do in 15 days and One women can do in 60 days
Step-by-step explanation:
let us assume Men as X and women as Y , so A.T.Q
we can write:
(2X + 7Y)×4 = ( 4X + 4Y )
by solving the above equation we get
X= 4 Y ( It means one man is equal to 4 women )
So from above equation by putting the value of X in terms of Y
2X + 7Y = 4
8Y + 7Y = 4
15 Y = 4 days
15 women can complete the work in 4 days one women can do in 60 days.
Like wise Putting the value of Y in terms of X in the equation we can get the result as One men can do in 15 days.