2 metal spheres have radii r and 2r and emit thermal radiation with max. intensifies at wavelength lemda and 2 lemda. The respective ratio of radiant energy emitted by the per second
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Answered by
5
The respective ratio of radiant energy emitted by the per second is 4:1.
Let the intensities at wavelengths be = λ and 2 λ.
Power = P = σT4A
For the first metal sphere, -
λT = K
λT1 = K
T1 = T
For the second metal sphere, -
2 λT2 = K
T2 = T/2
The power for both the metals will be -
p1 α T1² r² and p2 α T2² r²
P2 α ( T/2)² (2r)²
Thus,
P1/P2 = E1/E2
= 4:1
Thus, the respective ratio is 4:1
Answered by
5
Answer: 4:1
Explanation:
Use Stefan's law and Wein's displacement to solve this question and you'll get the answer. Hope this helps. :)
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