2 Mg + 6 HCL --> 2 MgCl3 + 3 H2
if you reacted 25.0 g of magnesium, how many grams of hydrogen gas will form?
Answers
Explanation:
A chemical equation shows the reactants (left side) and products (right side) in a chemical
reaction. A balanced equation shows, in terms of moles, how much of each substance is
involved in the reaction. Stoichiometry is the study of the relationships of quantities of
substances in a chemical reaction.
Consider the reaction:
(1) FeCl3 (aq) + 3NaOH (aq) → Fe(OH)3 (s) + 3NaCl (aq)
This balanced equation tells us: one mole of iron(III) chloride reacts with three moles of sodium
hydroxide to produce one mole of iron(III) hydroxide and three moles of sodium chloride.
Several mole ratio fractions are possible:
3 mol NaOH 1 mol FeCl3 3 mol NaCl
or or and others
1 mol FeCl3 1 mol Fe(OH)3 1 mol FeCl3
You recognize these as conversion factors. The first relates moles of the two reactants; the
second and third relate one of the reactants to one of the products.
No matter how much of each reactant there is to start with they will react only in the ratio of 1
mol FeCl3 / 3 mol NaOH. If exactly one mole of FeCl3 and three moles of NaOH are brought
together, both reactants will be completely consumed. If one mole of FeCl3 and five moles of
NaOH are brought together, only three moles of the NaOH will react; two moles of NaOH will be
left unreacted. If three moles of FeCl3 and three moles of NaOH are brought together, two
moles of FeCl3 will remain unreacted.
EXAMPLE: What mass of sodium hydroxide is needed to react completely with 10.0 g of
iron(III) chloride?
The conversion sequence is:
A B C
g FeCl3 mol FeCl3 mol NaOH g NaOH
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