2 MG + O2 = 2 MG
Using the above chemical equation calculate the amount of magnesium oxide that will be formed when
a) 192 gram of magnesium is burnt in excess of air.
b) 96 gram of magnesium is burnt in the excess of air.
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1
Answer:
b
Explanation:
2Mg+O
2
→2MgO
According to the reaction 2 mol (or 2×24.3=48.6g) Mg reacts with 32 g oxygen. 1 g of Mg requires =
48.6
32
=0.66g oxygen but given oxygen is 0.5 g ∴ oxygen is the limiting reagent
0.5 g oxygen can burn ==
32
48.6
×0.5=0.75g Mg
Excess of Mg left =1−0.75=0.25g
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