Question

2 MG + O2 Arrow to 2MGO using the above chemical equation calculate the amount of magnesium oxide that will be formed when (a)192 gram of magnesium is burnt in excess of air (2)96 gram of magnesium is burnt in excess of air​

Answer 1

Answer:

Explanation:

As air is excess, Mg is the limiting reagent.

2Mg + O2 ----> 2MgO.

Here 1 mol Mg gives 1 mol MgO.

(a) Number of moles of Mg = 192/24= 8.

8 moles Mg gives 8 moles MgO.

Therefore, amount of MgO formed= 8×Molar mass of MgO = 8×40 = 320g.

(b)Number of moles of Mg = 96/24= 4.

8 moles Mg gives 8 moles MgO.

Therefore, amount of MgO formed= 4×Molar mass of MgO = 4×40 = 160g.

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