Question

2 mol of an ideal gas at 540 K has volume 43.2 L. What is the pressure (in atm) ?

Answer 1

Answer:

pls see the attachment

Answer 2

Answer:

2.0525atm

Explanation:

Given:

n=2mol

T=540K

V=43.2L

P=?

PV=nRT

P=nRT/V

P=2×0.0821×540÷43.2

P=88.668/43.2

P=2.0525atm.

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