Question

2 mol of c5h12 reacts with 8 mol of o2 to form co2 and h2o.the amount of co2 formed is

Answer 1

Hey ✌,

C5H12 + 8O2 ----> 5CO2 + 6H2O

Actually,
=>72 g of C5H12 reacts with 256 g of O2.
=>1 g of C5H12 reacts with 256/72 g of O2.
=>1 g of C5H12 reacts with 3.55 g of O2.

But given,
=>2 mol i.e. 144g of C5H12 reacts with 2048 g of O2
=>1 g of C5H12 reacts with 2048/144 g of O2
=>1 g of C5H12 reacts with
14.22 g of CO2

So, O2 is a limiting reagent.

Since, product of the reaction depends upon limiting reagent.

Actually,
=>256 g of O2 reacts with 220 g of Co2
=>1 g of O2 reacts with 220/256 g of CO2

Given,
=>8 mol of O2 i.e. 2048 g of O2 will reacts with 220/256*2048 g of CO2
= 1760 g of CO2.

So, amount of CO2 formed is 1760 g.
In terms of moles,
no. of moles=given mass/molar mass
=1760/44
=40.

So, 40 moles of CO2 is formed in reaction.

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