Question

2 mol of H2S and 11.2 l of SO2 at NTP reacts to form x mol of sulphur;x is?

Answer 1

Answer:1.5

Explanation:

we have, 11.2 L of SO

2

​

= 0.5 mole

for 1 mole of SO

2

​

we require 2 moles of H

2

​

S

and for 0.5 mole of SO

2

​

we require 1 moles of H

2

​

S

so, we have SO

2

​

as a limiting reagent

1 mole of SO

2

​

form 3 mole of sulphur

0.5 mole of SO

2

​

produce S = 0.5 * 3 = 1.5 mole