Question

2 mole of H2s and 11.2dm3 of SO2 at S.T.P reacts to form moles of sulphur?

Answer 1

Answer:

1.5 mole

Explanation:

We have,

11.2 L of SO2

At STP 1 mole of SO2 contains 22.4 L volume

so, 11.2 L of SO2 carries 0.5 mole of SO2

Now,

2H2S +SO2 = 2H2O + 3S

for 1 mole of SO2 we require 2 moles of H2S and for 0.5 mole of SO2.

we require 1 moles of H2S

so, we have SO2 as a limiting reagent

1 mole of SO2 form 3 mole of sulphur

0.5 mole of SO2 produce S = 0.5 * 3 = 1.5 mole