Question

2 mole of He gas is heated from 20 degree C to 40 Degree C in a closed container then find Q,delta U ,and W​

Answer 1

Answer:

R=8.31Jmol

−1

deg

−1

=

4.18

8.31

cal mol

−1

deg

−1

=1.99cal mol

−1

deg

−1

We know that C

P

−C

V

=R

or C

V

=C

P

−R=7.03−1.99=5.04cal mol

−1

deg

−1

Heat absorbed by 5 mole of oxygen in heating from 10

o

C to 20

o

C

=5×C

V

×ΔT=5×5.04×10=252cal

Since, the gas is heated at constant volume, no external work is done,

i.e., w=0

So, change in internal energy will be equal to heat absorbed,

ΔU=q+w=252+0=252cal