Question

2 mole of He gas is heated from 20 degree C to 40 Degree C in a closed container then find Q,delta U ,and W and pls no baakbaas​

Answer 1

Answer:

Average Energy of 20 moles of diatomic gas =n×

2

5

×RT=20×

2

5

×RT=50RT

Average Energy of 12 moles of diatomic gas +16 moles of monoatomic gas (8 moles⇌16 moles)

=12×

2

5

×RT+16×

2

3

×RT=54RT

Heat supplied to the gas =54RT−50RT=4RT