Question

2 mole of n2 is mixed with 6 mol of h2 in a closed vesselbof 1 ltr capacity . If 50% of n2 is converted into nh3 at equilibrium the value of kc

Answer 1

1 mole of n2 reacts with 3 moles of h2

2 moles of N2 will react with 6 moles of H2

Now, 1 mole of N2 give = 2 moles of NH3

Then, 2moles of N2 give = 4 moles of NH3

But 50% of N2 (1 mole) reacts to give = 2 moles of NH3

N2 + 3H2 ---- 2NH3

Initial 2 6 0

At equilibrium 1 3 2

Kc = [ NH3]2 / [N2][H]3 = 1 /[ (1) (3)3] = 1/ 27 = 3.7 * 10-2

Answer 2

Answer:Ammonium carbonate when heated to 200 degreeC gives a mixture of NH3 and Co2 vapour with a density of 13.0. What is the degree of dissociation of ammonium carbonate

Explanation: