Question

2 mole of zinc is dissolved in HCL at 25degree celsius . calculate the work done in open vessel

Answer 1

SoluTion :-

$\sf {\fbox {Given}}\\\\\\\sf {n=2}\\\\\sf {T=25^{o} = 298K}\\\\\sf {R=8.314 J/mol.K}\\\\\\\\\sf {W is the work done.}\\\\\\\sf {W\ = \ -\ P\Delta V}\\\\\sf {= - nRT}\\\\\sf {W=-2 \times 8.314 \times 298}\\\sf {=-4.955\ kJ}$

Answer 2

Answer:

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