2 mole of zinc is dissolved in hcl at25 c calculate work done
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Answer:
-4.955 kilo joule (kJ)
Explanation:
Given n=2; T=25
o
C=298K; R=8.314 J/mol.K
W is the work done.
W=−P△V
=−nRT
W=−2×8.314×298
=−4.955 kJ
hope it helps
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