Question

2 moles each of liquid a and b ate dissolved to form an ideal somution. What will be the mole fraction of b in vapoir state

Answer 1

Answer:

We know that, mole fraction can be calculated using the following formula:

$P_{B} =P_{T} *X_{B}$

Here $P_{B}$ is partial pressure of B=100 mm Hg as in the vapor phase the partial pressure of B will be equal to its vapor pressure in pure state.

And $P_{T}$=(100+200)mm of Hg

so we get

$X_{B} =P_{B} /P_{T}$

=200/300

=2/3