2 moles of a diatomic gas is heated to double its volume while maintaining 2
atm pressure. If its initial temperature is 27°C then work done is nearly
4000 J
5900 J
5040 J
6000 J
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2 crystals my be used in this sustence
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Answer:
The initial temperature for the process is 300 K.
Now, following Charles' Law, where for a constant pressure, if volume is doubled, even the temperature will get doubled.
New temperature is 600 K.
The work done for the process will be,
W = nRδT
W = 0.1×2×(600−300)
W = 6000 cal
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