Question

2 moles of a gas at 0.75 atm and 20.0°C what is the volume?

Answer 1

please refer to the attachment file given mate.

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Answer 2

Answer:

64.06 L

Explanation:

Given :

Pressure P = 0.75 atm

No. of moles = 2 moles

Temperature T = 20 C = 293 K

We have find Volume V :

Using ideal gas equation :

P V = n R T

Value of R ( gas constant ) = 0.082 L atm mol⁻¹ K⁻¹

= > V = n R T / P

Putting values here we get :

= > V = ( 2 × 0.082 × 293 ) / 0.75 L

= > V = 48.052 / 0.75 L

= > V = 64.06 L

Therefore we get required answer.