Question

2 moles of an ideal gas at temperature 27℃ is heated isothermally from volume v to 4v . if R=2 cal/mol k, then the heat input in this process is approximately?​

Answer 1

Answer:

The heat input in the process is 1663.55 J

Explanation:

As per the question:

No. of moles, n = 2

Temperature of gas, $T_{g} = 27^{\circ}C = 273 + 27 = 300 K$

Initial volume = V

Final Volume = 4V

R = 2 cal/mol

Now,

The expansion took place isothermally, we use the eqn:

$Q = nRT_{g}ln(\frac{4V}{V}$

where

Q = Heat input

$Q = 2\times 2\times 300ln4 = 1663.55 J$