2 moles of an ideal gas have pressure of 10 atm at 27°C. Calculate its volume
Answers
Answered by
4
Given:
Moles of Gas = 2
Temperature = 27°C = 300k
Pressure = 10atm = 1013.25 kPa
To find:
Volume
Solution:
Gas equation: PV = nRT
where,
P = Pressure
V = Volume
n = no. of moles
R = Gas constant (8.314 J/k mol)
Substituting given data:
1013.25 x V = 2 x 8.314 x 300
V = 2 x 8.314 x 300/1013.25
V = 4988.4/1013.25
V = 4.9 L
Answered by
1
Explanation:
The ideal gas law, also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions, although it has several limitations. It was first stated by Benoît Paul Émile Clapeyron in 1834 as a combination of the empirical Boyle's law, Charles's law, Avogadro's law, and Gay-Lussac's law. The ideal gas law is often written in an empirical form: PV=nRT where P, V and T are the pressure, volume and temperature; n is the amount of substance; and R is the ideal gas constant. It is the same for all gases. It can also be derived from the microscopic kinetic theory, as was achieved by August Krönig in 1856 and Rudolf Clausius in 1857. Note that this law makes no comment as to whether a gas heats or cools during compression or expansion. An ideal gas may not change temperature, but most gases like air are not ideal and follow the Joule–Thomson effect.
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