2 moles of Ca(HCO3)2 on heating forms 1 mole of co2. The yield of co2 is
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Answer:
Given the reaction:
Ca(HCO
3
)
2
Δ
CaO+H
2
O+2CO
2
2 moles of 50% pure Ca(HCO
3
)
2
means one mole of Ca(HCO
3
)
2
.
So, according to reaction, 2 moles of CO
2
should form but, as only one mole formed.
Therefore, % yield =
2
100
=50%.
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