Question

2 moles of feso4 in acid medium are oxidest by how many moles of kmno4

Answer 1

You can solve this easily by using the equivalents concept

number of euivalents = number ofmoles x n factor

no. of moles of feso4  x n factor of feso4 = number of moles of kmno4 x n factor of kmno4 .

n factor of feso4 =1 [fe 2+--------> fe 3+]

n factor of kmno4 in acidic medium = 5 [ kmno4----------> Mn 2+]

so  by putting the values  we get

2 x 1 = no. of moles of kmno4 x 5

no. of moles of kmno4 = 2/5 =0.4

hope it helps:)