Question

2 moles of Hydrocarbon CnH2n burns in M moles of O2 to produce 10 moles of H2O as one of the products find M...
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Answer 1

Answer:

M = 15.

Explanation:

If hydrocarbon CnH2n burns following reaction occur :-

CnH2n + O2 = CO2 + H2O;

Balanced eqn. :-

2{CnH2n} + 3n{O2} = 2n{CO2} + 2n{H2O};

We have moles of H2O , i.e. . 10{H2O};

Therefore,

2n = 10;

n = 5;

So,

Moles of O2 (i.e.. 3n) are 15;

this verify for all hydrocarbon in form CnH2n;

eg. C2H4 :-

{C2H4} + 3{O2} = 2{CO2} + 2{H2O}  

=>>  5 {C2H4} + 15{O2} = 10{CO2} + 10{H2O}  

ANS = 15

Thank You :)