Question

2 moles of ideal gas is expanded reversible is from 4 atm to 3 atm at constant temperature of 300 K. calculate the work done (approx.)​

Answer 1

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Answer 2

The work done by the ideal gas is –1396KJ

Given:

Number of moles of ideal gas,n= 2 moles

P1 , Pressure before expansion=4atm

P2, Pressure after expansion= 3 atm

T, Temperature=300K

Find :

Calculate the work done by ideal gas.

Solution:

Formula used:

$\: \: \:W=–nRTln \times \frac{p1}{p2}$

$w = - 2 \times 8.31 \times 300ln \times \frac{4}{3}$

W=–2 x 8.31 x 300 x 0.28

w= –1396KJ

Hence the work done by the ideal gas is –1396KJ

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