Question

2 moles of monatomic gas at temperature 27°C is
maed with 3 moies of diatomic gas at temperature
127°C. then temperature of mixture is
approximately
(1) 9990
3 37°C
(2) 57°C
(4) 87°C
-​

Answer 1

Answer:

The temperature of the mixture is T = 154°C

Explanation :

As we know that

Total internal energy after mixing and before mixing will be same so let the final temperature is T.

Total number of moles = 2 moles + 3 moles = 5 moles

Lets suppose the initial temperature = To = 27°C

the final temperature = 127°C

5CvT = 2Cv27°C + 3Cv127°C

After cancellation

T = 154°C

Hence the temperature of the mixture is T = 154°C