Question

2 moles of monatomic gas at temperatures 27°c is mixed with 3 moles of diatomic gas at temp 127°c then temperature of mixter is?

Answer 1

The temperature of the mixture is T = 154°C

Explanation:

As we know that

Total internal energy after mixing and before mixing will be same so let the final temperature is T.

Total number of moles = 2 moles + 3 moles = 5 moles

Lets suppose the initial temperature = To = 27°C

the final temperature = 127°C

5CvT = 2Cv27°C + 3Cv127°C

After cancellation

T = 154°C

Hence the temperature of the mixture is T = 154°C

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Answer 2

Answer:

98.42°C

Explanation:

From the ideal gas equation

PV=nRT

U1=nCv∆T

U1=2×3/2R×(273+27)

U1=900R

U2=n'Cv'∆T

U2=3×5/2R×(273+127)

U2=3000R

Umix=U1+U2

Umix=3900R

T=3900R/10.5

T=371.42k

T=98.42°C