2 moles of N2 (g) and 3 moles of H2 (g) are mixed to produce NH3 (g). Calculate the amount of NH3 (g) formed.
Answers
Answer:
2 moles of NH3
Explanation:
N2(g) + 3H2(g) → 2NH3(g) - Haeber's process
2 moles of N2 and 3 moles of H2 are reacting. Here the limiting reagent is H2 while N2 is excess reagent. Therefore, 1 mole of N2 will react with 3 moles of H2 to form 2 moles of NH3.
Answer: 2 moles of N2 (g) and 3 moles of H2 (g) are mixed to produce 2 moles of NH3 (g).
Explanation: 2 moles of N2 (g) and 3 moles of H2 (g) are mixed to produce 2 moles ofNH 3 (g).
Here is the equation
N₂ (g) ₊ 3H₂ (g) → 2NH₃ (g)
Addition of 2 moles of nitrogen and 3 moles of hydrogen gives 2 moles of ammonia. This is an exothermic reaction in which energy is released.
The chemical equation involved in the haber process. The haber process is the most important process for the manufacture of ammonia . In this process ammonia is formed by the use of atmospheric nitrogen on reaction with hydrogen.
To know more about exothermic from the given link
https://brainly.in/question/19363174
To know more about haber process from the given link
https://brainly.in/question/1561090
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