Question

2 moles of N2 is mixed with 6 moles of H2 in a closed vessel of 1l capacity. if 50% N2 is converted into NH3 at equilibrium, the value of kc for the reaction is

Answer 1

50 % N2 changes to nh3  Means 1 mole of n2   Because 2 moles are given and 50% of 2 moles is 1 mole    So 50 % N2 is given so h2 also 50%  changes to nh3means 3 mole So of h2 changel to nh3    Total moles of nh3 at equilibrium is 4 and N2 = 1 h2 = 3   Use law of mass action  Kc = [Nh3 ]^2 ÷ [N2 ] × [ H2]  KC = 4^2 ÷ 1 × 3  KC = 16 ÷ 3  KC = 5.333   hope it helps you  Mark as brainlist plz