2 moles of pcl5 are heated to equilibrium in a closed vessel at constant temperature. if the degree of dissociation is 0.5.detemine the total number of moles in the equilibrium mixture
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Dear Student,
PCl5 ↔ PCl3 + Cl2Initial C 0 0 At equil. C(1−α) Cα CαTotal number of moles at equilibrium = C(1−α)+Cα+Cα=C(1+α)Here, α= 0.5C=2Therefore, Total number of moles= 2(1+0.5)=2(1.5)=3mol
PCl5 ↔ PCl3 + Cl2Initial C 0 0 At equil. C(1−α) Cα CαTotal number of moles at equilibrium = C(1−α)+Cα+Cα=C(1+α)Here, α= 0.5C=2Therefore, Total number of moles= 2(1+0.5)=2(1.5)=3mol
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hi,tanu I am also in 9th but not good in chemistry ,will you assist me ,I will help u in math ,recently I got 80/80 in math
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