Math, asked by mohitrohan1313, 1 month ago

2. Mrs Jain is 5 times as old as her daughter. Six years later she will be three times as old as her daughter.
Find the present age of Mrs Jain.

Answers

Answered by yetanothersadkid0816
6

Answer

Step-by-step explanation:

Let Mrs Jain's daughter = x

So, Mrs Jain = 5x

ATQ, equation

5x+6 = 3(x+6)

5x+6 = 3x+18

5x-3x = 18-6

2x = 12

x = 12/2

x = 6

Mrs Jain's daughter = 6

Answered by fizaar1901
2

Answer:

Mrs Jain is 30 years old.

Step-by-step explanation:

Let daughter's age be x years.

So Mrs Jain's age would be 5x years. ( as per question).

Six years later :

Daughter's age would be x+6 years &

Mrs Jain's age would be 5x+6 years.

According to given relation , Mrs Jain would be 3 times as old as her daughter.

So,

5x+6 = 3(x+6).

5x+6 = 3x+18

5x-3x = 18-6

2x = 12

x = 6.

Therefore , the daughter's age is 6 years & that of Mrs Jain is 5*6 = 30 years.

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