Math, asked by donaldjoseph, 11 months ago

2^(n-1) = 256 ? Please give me the answer

Answers

Answered by varsha1409
2
2^(n-1) = 2^8

n-1= 8
n= 9


hope it's help you
Answered by bharathparasad577
0

Answer:

Concept:

Use the property of equality of exponential functions to solve exponential equations with the same base. If p is  a positive number, then p^{a}=p^{b} if and only if a=b. In other words, if the bases are the same, the exponents must be the same as well.

Step-by-step explanation:

Given:

An equation , 2^{(n-1)} =256\\

To find:

Value of n

Solution:

  • Write 256 in terms of 2

                                           256= 16 * 16\\\\256 =2^{4} *   2^{4}\\\\256= 2^{8} \\                                                

  •  It is given that , 2^{(n-1)} = 256

                                            2^{(n-1)} =2^{8}\\ \\

  • As base is equal on both sides , equate the powers on both sides.

                                    n-1=8\\\\n=8+1\\\\n=9

Hence, value of n=9

#SPJ3

Similar questions