Question

2/N 162
What is the sum of the first 10 natural numbers ?
(i)
(A)
55
(B) 20
(C) 65​

Answer 1

Answer:

55

Explanation

Here the AP formed will be 1,2,3.....

So, a=1

d=2-1=1

n=10

Sn = n/2 [2a + (n - 1)d]

= 10/2 [2 × 1 +(10 - 1) × 1]

= 5 [2 + 9]

= 5 × 11

= 55

You also can simply add those numbers like 1+2+3+4+5+6+7+8+9+10=55

*Natural numbers are the counting numbers*