2^n+2-2^n+1+2^n÷2^n
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Answer:
n2<2n
P(n) is the statement n2<2n
Claim: For all n>k, where k is any integer, P(n)
(since k is any integer, I assume I have to prove this for positive and negative integers)
So let base case be P(1), and I have to prove P(n) for n≥1 and n<1
P(1) is 12<21 which is clearly true.
Induction hypothesis: k2<2k
Inductive step (k+1)2<2(k+1)
(k+1)2=k2+2k+1
k2+2k+1<2k+2k+1 by inductive hypothesis
Not sure how to proceed. Is my previous intuition that I have to prove this for n≥1 and n<1 correct?
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Hope this helps u.......
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