2^n+2-2^n+1+2^n=c×2^n.Find the value of C.
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2^(n+2)=2^n*4
2^(n+1)=2^n*2
So,
By simplifying it
2^n*4-2^n*2=C*2^n
Taking the 2^n common from the LHS, we get is now 2^n(4-2)=C*2^n
2*2^n=C*2^n
From comparison of LHS & RHS
We find the value of: C=2
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