Question

2 n force is applied to an object and it makes displacement 5 m in the direction perpendicular to force. Calculate the work done by the force.​

Answer 1

Topic :- Work energy and Power

$\maltese\:\underline{\sf AnsWer :} \: \maltese$

• Force Applied to an object (F) = 2 N
• Displacement of the body (s) = 5 m
• θ = 90° [∵ Displacement is done in the direction perpendicular to the Force]

We need to find the work done by the body. To calculate work done by the body we will use the given below formula :

$\longrightarrow\:\sf Work \: Done = Fs \cos (\theta)$

Now, simply add the known values from the Question in the above given formula :

$\longrightarrow\:\sf Work \: Done = 2 \times 5 \cos (90^{ \circ} )$

$\longrightarrow\:\sf Work \: Done = 10 \cos (90^{ \circ} )$

$\qquad \qquad\tiny \dag \: \underline{\sf \cos \: (90^{ \circ}) = 0}$

$\longrightarrow\:\sf Work \: Done = 10 \times 0$

$\longrightarrow\: \underline{ \boxed{\sf Work \: Done = 0 \: J}}$

Hence,the work done by the body is 0 J.

Answer 2

Answer:

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