Math, asked by chinmayeecm2006, 6 hours ago

2. Namitha travels 600km to her home partly by train and partly by bus She takes & hours of she travels 120 kom by train and the remaining by bus. If the travels 200 km by train and the remaining by bus, she takes 20 minutes longer. the speed of the train and the bar seperately.​

Answers

Answered by tarunrahav
1

Answer:

Case 1 : Total distance =600 km

distance covered by train =120 km

time taken by train =120/x km/h

x= speed of the train

Distance covered by car =(600−120)=480 km

Time taken by car =(  

y

480

) km/h

total time taken =  

x

120

+  

y

480

=8

                               

x

30

+  

y

120

=2

Case II :

total distance covered by train =200 km

total time taken by train =200/x

total distance covered by car =600−200=400

total time taken by car =  

y

400

 km/h

total time taken =8×(20/60)=25/3

x

200

+  

y

400

=  

3

25

 

⇒600/x+  

y

1200

=25

Let 1/x be u and  

y

1

 be v

equation are then  

600u+1200v=25⇒30u+120v=2

multiplying equation (1) by 20 and substrating the equations we get :

1200v=15,v=15/1200

Since, 1/y ⇒y=  

15

1200

=80 km/h

speed of car =  

80 km/h

 

multiplying equation (1) on 10 and substracting equations we get

300u=5

u=5/300⇒1/x=u

speed of train =x=  

5

300

=60 km/h  

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