Question

2 Neha invested 310,000 at the rate
10 p.c.p.a. in a scheme for 3 years. Find the
amount she gets after 3 years, if the interest
is compounded annually.​

Answer 1

Answer:-

Given:-

Principal (P) = Rs. 3,10,000

Rate of interest (R) = 10 %

Time period (T) = 3 years.

We know that;

$\boxed{\sf \: Amount(A) = P \bigg(1 + \frac{R}{100} \bigg) ^{T}}$

Hence,

$\implies \sf \: A = 310000 \bigg( 1 + \frac{10}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \bigg( \frac{100 + 10}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \times \bigg( \frac{110}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} \\ \\ \\ \implies \boxed{\sf \: A = Rs. \: 4,12,610}$

∴ Neha receives Rs. 4,12,610 at the end of 3 years.

Answer 2

Answer:

Given :-

• Neha invested Rs 310000 at the rate of 10% p.a in a scheme for 3 years.

To Find :-

• What is the amount she gets after 3 years.

Formula Used :-

$\sf\boxed{\bold{\pink{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^{n}}}}$

where,

• A = Amount
• P = Principal
• r = Rate of Interest
• n = Time

Solution :-

Given :

• Principal (P) = Rs 310000
• Rate of Interest (r%) = 10%
• Time (n) = 3 years

According to the question by using the formula we get,

↦ $\sf A =\: Rs\: 310000\bigg(1 + \dfrac{1\cancel{0}}{10\cancel{0}}\bigg)^{3}$

↦ $\sf A =\: Rs\: 310000\bigg(1 + \dfrac{1}{10}\bigg)^{3}$

↦ $\sf A =\: Rs\: 310000\bigg(\dfrac{11}{10}\bigg)^{3}$

↦ $\sf A =\: Rs\: 310\cancel{0}\cancel{0}\cancel{0} \times \dfrac{11}{1\cancel{0}} \times \dfrac{11}{1\cancel{0}} \times \dfrac{11}{1\cancel{0}}$

↦ $\sf A =\: Rs\: 310 \times 11 \times 11 \times 11$

↦ $\sf A =\: Rs\: 3410 \times 121$

➠ $\sf\bold{\red{A =\: Rs\: 412610}}$

$\therefore$ The amount she gets after 3 years is Rs 412610 .