Question

2 Neha invested 310,000 at the rate
10 p.c.p.a. in a scheme for 3 years. Find the
amount she gets after 3 years, if the interest
is compounded annually.


ANSWER: Answer:-
Given:-

Principal (P) = Rs. 3,10,000

Rate of interest (R) = 10 %

Time period (T) = 3 years.

We know that;

\begin{gathered} \boxed{\sf \: Amount(A) = P \bigg(1 + \frac{R}{100} \bigg) ^{T}} \\ \end{gathered}
Amount(A)=P(1+
100
R
​
)
T

​

​


Hence,

\begin{gathered} \implies \sf \: A = 310000 \bigg( 1 + \frac{10}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \bigg( \frac{100 + 10}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \times \bigg( \frac{110}{100} \bigg) ^{3} \\ \\ \\ \implies \sf \: A = 310000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} \\ \\ \\ \implies \boxed{\sf \: A = Rs. \: 4,12,610} \\ \end{gathered}
⟹A=310000(1+
100
10
​
)
3

⟹A=310000(
100
100+10
​
)
3

⟹A=310000×(
100
110
​
)
3

⟹A=310000×
10
11
​
×
10
11
​
×
10
11
​

⟹
A=Rs.4,12,610
​

​


∴ Neha receives Rs. 4,12,610 at the end of 3 years.

​

Answer 1

Answer:

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Step-by-step explanation:

of the above

Answer 2

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