Question

2.
No. of atoms in 4.25 g. of NH, is approx :-
(1) 1 x 1023
12–1.5 1023
(3) 2 x 1023
(4) 6 x 1023​

Answer 1

Answer:

it is NH3 not NH

$no \: of \: atom \: = no \: of \: moles \: \times 6.022 \times {10}^{23}$

$no \: of \: moles \: = \frac{given \: weight}{molar \: weight \: }$

no of moles =4.25/17= 0.25 moles

$no \: of \: atom \: = 0.25 \times 6.022 \times {10}^{23}$

$no \: of \: atom \: = 1.50 \times {10}^{23}$

$= 1.5 \times {10}^{23}$

therefore it is option B but it is not in negative