Question

2 nos are in ratio 3:5.If each is increased by 10 the ratio between the new numbers so formed is 5:7.Find the original numbers​

Answer 1

Answer:

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Answer 2

Given:

Two number are in ratio 3:5

So,

Let one number be 3x and

Let another number be 5x

Accoding to the question

When 10 is added/increased to both numerator and denominator the fraction becomes 5:7

So,

The eqation which is formed is

$\boxed{\implies \frac{3x\bf{+10}}{5x\bf{+10}}=\frac{5}{7}}$

∵ By doing cross multiplication, we get,

⇒ 7(3x + 10) =5(5x + 10)

⇒ 21x + 70 = 25x + 50

⇒ 70 - 50 = 25x - 21x

[By tansporting 50 to LHS and 21x to RHS ]

⇒ 20 = 4x

⇒ 20 ÷ 4 = x

[By taking 4 to LHS]

∴ The value of x = 5

Now,

3x = 3 * 5 = 15

And

5x = 5 * 5 = 25

Hence,

• The fraction is 15/25

- - -

Verification:

When 10 is added to bothnumerator and denominator

$\frac{15\bf{+10}}{25\bf{+10}}=\frac{25}{35}$

[Now, 25/5 = 5 and 35/5 = 7]

25/35 = 5/7 = 5:7

Hence,

Verified